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UVa 729 The Hamming Distance Problem

UVa 729 The Hamming Distance Problem

Method: Bruteforce, all combinations. Permutation. Backtracking.
Trick: Finding all the results is pretty easy using any Basic Backtracking code but you have to sort them. So? Dont work with 1s work with 0s. Or just use next_permutation( ) from STL, your choice. Optimizations: Pregenerating all combinations might give you a better runtime, didnt try it.

Sample Input:

1

16 7

Sample Output:

Please find it using UVA Toolkit (www.uvatoolkit.com)

/* Faith-M */

//Headers
#include <set>
#include <map>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <cctype>
#include <cstdio>
#include <string>
#include <vector>
#include <cassert>
#include <cstdlib>
#include <cstring>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <climits>
#include <clocale>
//Defines
#define pow2(i) (1<<i)
#define bit(i) (1<<i)
#define isOdd(i) (i&1)
#define isEven(i) (!(i&1))
#define isPrime(i) ((i==2) || ((i&1) && !pTest[i])) //pTest has to be the bool arrays name
#define sz(i) i.size()
#define vec(type,name) vector< type > name
#define rep(i,a,b) for(int i=a ; i<=b ; i++)
#define swap(type,a,b) {type t=a; a=b; b=t;}
#define sum(a,n) ( (n*(n+1)/2) - (a-1)*a/2 )
#define iscap(i) (i>=A&&i<=Z)
#define issmall(i) (i>=a&&i<=z)
#define isnum(i) (i>=0&&i<=9)
#define issymbol(i) (!(i>=a&&i<=z) && !(i>=A&&i<=Z) && !(i>=0&&i<=9))
#define mk(i,j) make_pair(i,j)
#define ERROR 1e-11
//Type Defs
typedef long long lint;
typedef unsigned long long ulint;
typedef long double ldouble;

using namespace std;

int st[20];

void func(int n, int h, int cnt, int x)
{

 if (cnt >= h)
 {
 for (int j=1 ; j<=n ; j++)
 {
 printf("%d",st[j]);
 }
 printf(" ");


 return;
 }

 for (int i=x ; i<=n ; i++)
 {
 if (st[i] == 1)
 {
 st[i] = 0;

 func(n,h,cnt+1,i+1);

 st[i] = 1;
 }
 }

 return;
}

int main()
{
 //freopen("input.txt","r+",stdin);
 //freopen("output.txt","w+",stdout);/**/

 // TEST CASE //
 int kase=1, kounter=1;/**/

 int n, h;

 bool blnk = false;

 scanf("%d",&kase);

 while ( kase-- )
 {
 if (blnk) printf(" ");
 else blnk = true;

 for (int i=1 ; i<=20 ; i++)
 {
 st[i] = 1;
 }

 scanf("%d %d",&n,&h);

 func(n,n-h,0,1);
 }


 return 0;
}

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