Saturday, October 29, 2016
UVa 12444 Bits Pieces
UVa 12444 Bits Pieces
Trick: Analyze the problem a bit with the given Samples.
When for a particular bit
C = 1 & D = 1, obviously both the numbers have to have 1 in that position
C = 0 & D = 1, if this case occurs for the first time make the bit in B = 1 & A = 0, otherwise B = 0 & A = 1. This ensures |B-A] Minimality & A<=B.
No other combination is possible.
/* Faith-M */
//Headers
#include <set>
#include <map>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <cctype>
#include <cstdio>
#include <string>
#include <vector>
#include <cassert>
#include <cstdlib>
#include <cstring>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <climits>
#include <clocale>
//Defines
#define pow2(i) (1<<i)
#define bit(i) (1<<i)
#define isOdd(i) (i&1)
#define isEven(i) (!(i&1))
#define isPrime(i) ((i==2) || ((i&1) && !pTest[i])) //pTest has to be the bool arrays name
#define sz(i) i.size()
#define vec(type,name) vector< type > name
#define rep(i,a,b) for(int i=a ; i<=b ; i++)
#define swap(type,a,b) {type t=a; a=b; b=t;}
#define sum(a,n) ( (n*(n+1)/2) - (a-1)*a/2 )
#define iscap(i) (i>=A&&i<=Z)
#define issmall(i) (i>=a&&i<=z)
#define isnum(i) (i>=0&&i<=9)
#define issymbol(i) (!(i>=a&&i<=z) && !(i>=A&&i<=Z) && !(i>=0&&i<=9))
#define mk(i,j) make_pair(i,j)
#define ERROR 1e-11
//Type Defs
typedef long long lint;
typedef unsigned long long ulint;
typedef long double ldouble;
using namespace std;
pair <lint, lint> find( lint c, lint d )
{
lint a=0, b=0, bit_c, bit_d;
bool fbit=true;
int i;
for (i=31 ; i>=0 ; i--)
{
if ((1<<i)&c) bit_c = 1;
else bit_c = 0;
if ((1<<i)&d) bit_d = 1;
else bit_d = 0;
if (bit_c == 1 && bit_d == 1)
{
a = a | (1<<i);
b = b | (1<<i);
} else if (bit_c == 0 && bit_d == 1)
{
if (fbit == true)
{
b = b | (1<<i);
} else
{
a = a | (1<<i);
}
fbit = false;
}
}
if ( (a&b) == c && (a|b) == d ) return make_pair(a,b);
else return make_pair(-1,-1);
}
int main()
{
//freopen("input.txt","r+",stdin);
//freopen("output.txt","w+",stdout);/**/
// TEST CASE //
int kase=1, kounter=1;/**/
lint c, d;
scanf("%d",&kase);
while (kase--)
{
cin >> c >> d;
pair <lint, lint> res = find(c,d);
if (res.first == -1) printf("-1 ");
else cout << res.first << " " << res.second << endl;
}
return 0;
}
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